twice as long to stop, so 1/2 the acceleration
v = at, so
20/10 m/s^2, then 20 m/s, then -20/20 m/s^2
A motor car accelerates for 10 seconds to attain a velocity of
20
m
/
s
2
. It continues with uniform velocity for a further 20 seconds and then decelerates so that it steps in 20 seconds. Calculate the acceleration and deceleration.
1 answer