A motor car accelerate for 10sec to attain a velocity of 20m/s. If continues and then decelerate so that is stop in 20sec. calculate (1) Acceleration (2) Deceleration (3) The Distance
6 answers
what does "If continues' MEAN?
1. a*t = 20 m/s. a*10 = 20, a = 2m/s^2.
2. V = Vo + a*t = 0. 20 + a*20 = 0, a = -1.0 m/s^2.
3. d1 = 0.5a*t^2 = 0.5*2*10^2 = 100 m.
V^2 = Vo^2 + 2a*d2 = 0.
20^2 + (-2)*d2 = 0, d2 = ?.
d = d1 + d2.
2. V = Vo + a*t = 0. 20 + a*20 = 0, a = -1.0 m/s^2.
3. d1 = 0.5a*t^2 = 0.5*2*10^2 = 100 m.
V^2 = Vo^2 + 2a*d2 = 0.
20^2 + (-2)*d2 = 0, d2 = ?.
d = d1 + d2.
I need the solution for the distance
Please add d1 and d2 to get the distance.
Can YOU solve the simple Eq.. to get d2 ??.
Can YOU solve the simple Eq.. to get d2 ??.
D1 D2
please I need the calculation