A mother is now two and a half times as old as her daughter. Four years ago the ratio of their ages was 3:1. Find the present age of the mother

1 answer

Let's denote the present age of the daughter as \( d \) years. Then, the present age of the mother is \( 2.5d \) years.

According to the problem, four years ago, the daughter's age was \( d - 4 \) years, and the mother's age was \( 2.5d - 4 \) years. At that time, the ratio of their ages was 3:1, which gives us the equation:

\[ \frac{2.5d - 4}{d - 4} = 3 \]

To eliminate the fraction, we can cross-multiply:

\[ 2.5d - 4 = 3(d - 4) \]

Expanding the right side:

\[ 2.5d - 4 = 3d - 12 \]

Now, let's rearrange the equation to isolate \( d \):

\[ 2.5d - 3d = -12 + 4 \]

\[ -0.5d = -8 \]

Dividing both sides by -0.5:

\[ d = 16 \]

Now that we have the daughter's age, we can find the mother's age:

\[ \text{Mother's age} = 2.5d = 2.5 \times 16 = 40 \]

Thus, the present age of the mother is \( \boxed{40} \) years.