First, we find the total number of bills in the envelope:
$10 bills: 5
$20 bills: 10
$50 bills: 15
Total bills = 5 + 10 + 15 = 30
The probability of selecting a $10 bill first is 5/30, which simplifies to 1/6. After selecting a $10 bill, there are 29 bills left in the envelope, with 15 of them being $50 bills. So, the probability of selecting a $50 bill second is 15/29.
Therefore, the probability of getting a $10 bill then a $50 bill is:
(1/6) * (15/29) = 15/174
So, the probability is 15/174.
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction. (1 point)
1 answer