First we need to find the total number of bills in the envelope:
5 + 10 + 15 = 30 bills
The probability of getting a $10 bill on the first selection is:
5/30 = 1/6
After removing the $10 bill from the envelope, there are now 29 bills left in the envelope. The probability of getting a $50 bill on the second selection is:
15/29
Therefore, the probability of getting a $10 bill then a $50 bill is:
(1/6) * (15/29) = 15/174
So, the probability of getting a $10 bill then a $50 bill is 15/174.
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra
randomly selects two bills without returning the first bill. What is the probability of getting a
$10 bill then a $50 bill? Write your answer in the simplest form of fraction. (1 point)
1 answer