The total number of bills in the envelope is 5 + 10 + 15 = 30 bills.
The probability of selecting a $10 bill first is 5/30 = 1/6.
After selecting the $10 bill, there are 29 bills left with 15 of them being $50 bills.
So, the probability of selecting a $50 bill second is 15/29.
Therefore, the probability of getting a $10 bill then a $50 bill is (1/6) * (15/29) = 5/58.
So, the probability is 5/58.
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction.(1 point)
1 answer