There are a total of 30 bills in the envelope.
The probability of selecting a $10 bill first is 5/30 = 1/6.
After selecting a $10 bill, there are 29 bills left, with 15 of them being $50 bills.
The probability of selecting a $50 bill second is 15/29.
Therefore, the probability of selecting a $10 bill then a $50 bill is (1/6) * (15/29) = 5/58.
So, the probability is 5/58.
A money envelope contains five $10 bills 10 $20 bills and 15 $50 bills Sandra randomly select two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill write your answer in the simplest form of fraction
1 answer
1 answer