A model rocket is launched straight upward with an initial speed of 51.3 m/s. It accelerates with a constant upward acceleration of 1.82 m/s2 until its engines stop at an altitude of 150 m. What is the maximum height reached by the rocket?

Answer 1

V^2 = Vo^2 + 2a*h
V^2 = 51.3^2 + 3.64*150 = 3177.69
V = 56.4 m/s.

hmax = (V^2-Vo^2)/2g
hmax = (0-56.4^2)/-19.6 = 162,3 m.