A model rocket is launched from a roof into a large field. The path the rocket can be modeled by the equation y=-0.04x^2+8.3x+4.3 where x is the horizontal distance in meters, from the starting point on the roof and y is the height in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

Answer 1

my answer is 208.02 meters

Answer 2

Since you want the distance horizontally from the starting point, you want y to be 4.3m which is the initial height, thus
0 = -.04x^2 + 8.3x
x(.04x - 8.3) = 0
x = 0 , which would be our starting point and
x = 8.3/.04 or 207.5 m

your answer would be the distance from a height of 4.3 m to the ground, which would not be a horizontal line

Answer 3

yas

Answer 4

will some one please give the answers i’ve been sick for like a month and procrastinated math and did everything else but i learned nothing and i’m not even supposed to be in algebra and i need help

Answer 5

The correct answer is 208.02 m

Answer 6

@Anonymous ...same bruh

Answer 7

the answer is 208.02 m

Answer 8

its 208.2

Answer 9

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