A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation

y = –0.04x2 + 8.3x + 4.3 , where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter.

208.02 m
416.03 m
0.52 m
208.19 m
I think it is A...?

5 answers

I am sure you meant
y = -.04x^2 + 8.3x+ 4.3
when it lands, y = 0
.04x^2 - 8.3x - 4.3=0
x = (8.3 ± √69.578)/.08
= 208.0167.. or a negative value of x

= 208.02 m

Thank you...

wow old question

Yea so old.

Ur mom