A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = –0.02x2 + 2.3x + 6, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? My mind is blank...

Question

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = –0.02x2 + 2.3x + 6, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?  My mind is blank...
 57.50 m
 115.00 m
 117.55 m
 235.10 m

DingDong · Accepted Answer

Its 117.55 ^^

Steve · Answer

it lands when the height (y) is zero. So, just solve for x in -0.02x2 + 2.3x + 6 = 0 just use the quadratic formula.

raychelz · Answer

bro thanks

ice spice · Answer

i guess it still works for the future highschool students 2023,2024,2025,2026,2027,2028,2029