To find the total storage of the mobile phone after buying the additional bytes, you need to add the original storage (which is not specified, but we'll denote it as \(X\) bytes) to the additional storage of 384,000,000,000 bytes.
The additional storage can be expressed in scientific notation as follows:
\[ 384,000,000,000 = 3.84 \times 10^{11} \text{ bytes} \]
Now, if we assume that the original storage is also in scientific notation and we want to express the total storage after adding the additional bytes.
Let’s denote the original storage as \(X\). The total storage would be:
\[ X + 384,000,000,000 \]
In scientific notation, \(384,000,000,000\) is \(3.84 \times 10^{11}\).
In your answer choices, the total storage is not explicitly indicated with an original amount, but if we look at the available choices regarding amounts that might seem like possible original storage amounts and would fit correctly based on the millions to billions concept along with the addition, let’s analyze the given:
The additional storage is \(3.84 × 10^{11}\). If the original storage were, say \(5.12 × 10^{11}\), we'd calculate:
\[ 5.12 × 10^{11} + 3.84 × 10^{11} = 8.96 × 10^{11} \]
However that does not match any of the given choices.
The closest option that represents an addition of \(384000000000\) to \(X\) would depend on original \(X\).
Thus simply adding \(384,000,000,000\) to any generic \(X\) won't give a specific choice without knowing \(X\). The key here is identifying:
So, if you already had a phone with \(8.96 × 10^{11}\) bytes, which isn't given in your choices either.
Based on taking just the additional, the multiple listed in options commonly blending a number like \(385,280,000,000\) or comparable better adds up:
385280000000 = \(3.8528 \times 10^{11}\), and is not simplified to exact max options but closely related to provided \(3.8 \).
So specific:
- The total storage might be \(3.84 × 10^{11} \) exactly for plain additional.
From the choices provided and based on common acceptance,
The most straightforward and likely total can be framed around \(385,280,000,000 = 3.8528 × 10^{11}\) usable.
So the pointed inquiry for complexity of this calculation,
I would suggest selecting:
385,280,000,000 as indicated simplest viewed.