a mobile phone holds 1.28 x 10^11 bytes of storage

1 answer

To understand the storage capacity of a mobile phone that holds \( 1.28 \times 10^{11} \) bytes, we can convert this value into more familiar units such as gigabytes (GB) or terabytes (TB).

1 byte = 8 bits
1 kilobyte (KB) = \( 10^3 \) bytes = 1,000 bytes
1 megabyte (MB) = \( 10^3 \) KB = 1,000,000 bytes
1 gigabyte (GB) = \( 10^3 \) MB = 1,000,000,000 bytes
1 terabyte (TB) = \( 10^3 \) GB = 1,000,000,000,000 bytes

Now, let's convert \( 1.28 \times 10^{11} \) bytes into gigabytes (GB):

\[ 1.28 \times 10^{11} \text{ bytes} = \frac{1.28 \times 10^{11}}{10^9} \text{ GB} = 1.28 \times 10^{2} \text{ GB} \]

This simplifies to:

\[ 1.28 \times 10^{2} , \text{GB} = 128 , \text{GB} \]

So, a mobile phone with a storage capacity of \( 1.28 \times 10^{11} \) bytes has approximately 128 GB of storage.