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a mixture of NaCl and NaBr has a mass of 2.06 g and is found to contain 0.75 g of na

what is the mass of NaBr in the mixture ?

2 answers

SciMann

Best Answer - Chosen by Voters

Let UNITs guide you; always USE THEM in your calculation to prevent errors

moles of Na in samp = 0.78 g/ atwt Na = ??

x moles NaBr * MW NaBr + (moles Na - x moles NaBr) * MW NaCl = 2.01 g

x moles NaBr = [2.01 g - moles Na * MW NaCl] / [MW NaBr - MW NaCl] = ??
g NaBr = x moles NaBr * MW NaBr

wt fraction = g NaBr/2.01g = ?? (0.049 wt fraction of NaBr)

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