A mixture of gases contains 64g of methane, 64g of oxygen and 64g of sulphur dioxide.

Question

The pressure of the mixture is 2l0kPa. What is the partial pressure (in kPa) of the methane
expected to be?

Answer 1

mols CH4 = g/molar mass = 64/16 = 4
mols O2 = 64/32 = 2
mols SO3 = 64/80 = 0.8
Total mol = 6.8
mol fraction CH4 = X_CH4 = 4/6.8 = 0.588 round to 0.59
pCH4 = XCH4*Ptotal
pCH4 = 0.59*210 = ? in kPa.