mm = molar mass
am = atomic mass
You have two equations and you solve the two equations simultaneously.
Let X = grams FeO and
let Y = grams Fe2O3.
equation 1 is X + Y = 10.0 g
The second equation is converting this 10.0 g into pure iron in terms of X and Y.
eqn 2 is X(am Fe/mm FeO) + Y(2 am Fe/mm Fe2O3) = 7.48 g
Solve these two equation for X and Y giving you grams FeO and Fe2O3.
Post your work if you get stuck. This is the chem part. The only thing left is the math.
A mixture of FeO and Fe2O3 with a mass of 10.0 g is converted to 7.48 g of pure Fe metal. What is the amount of FeO and Fe2O3 (in grams) in the original sample.
Not sure where to start. Any help is appreciated!
1 answer