No you need not go through that. The easy way is to determine the H2O lost (as in the previous problem), convert that to grams BaCl2.2H2O, then subtract the mass of BaCl2.2H2O from the total mass to find mass K2SO4.
Then %K2SO4 = (mass K2SO4/mass sample)*100 = ?
A mixture of BaCl2.2H2O (FM244.26) and K2SO4 (FM 174.26) is heated at 160C for an hour, causing the water molecules to leave. A sample originally weighing 2.0027 g weighed 1.9021 g after heating. Calculate the mass percent K2SO4 in the sample.
In a previous practice example, I had to find the weight percent of Ba, K, and Cl (K2S04 now replacing KCl). So how would I go about finding mass % of K2S04? Would I have to calculate weight percent of Ba, K2 and SO4 as well or is there something else?
Thank you.
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