H2 + O2 -> H2O
balancing this,
2H2 + O2 -> 2H2O
then we find the limiting reactant. To determine the limiting reactant, we get the moles of product from the given moles of reactant. Whichever yield less number of moles of product is the limiting reactant. thus,
4 mol H2 * (2 mol H2O / 2 mol H2) = 4 mol H2O
3 mol O2 * (2 mol H2O / 1 mol O2) = 6 mol H2O
thus, the limiting reactant is H2.
finally, to get the mass of water, we use the moles of H2O produced by H2O, and multiply this by the molecular mass of water. Note that the molecular mass of H2O = 18 g/mol. thus,
4 * 18 = 72 g H2O
a mixture of 4.00 moles of hydrogen and
3.00 moles of oxygen is ignited, forming water. what is the maximum amount of water in grams that can be formed?
1 answer