2NO + O2→2NO2
mols NO in 25 g = g/molar mass = 25/30 = approx 0.83
mols NO2 = 0.83 mols NO x (2 mols NO2/2 mol NO) = 0.83
0.83 mols x 22.4 L/mol @ STP = ?
You may want to check the numbers.
A mixture of 25.0g of NO and an excess of O2 reacts according to the balanced equation. 2 NO + O2→2NO2. How many liters of NO2 are produced at STP?
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