I would do this.
Ptotal = PH2O + PN2 + PO2
750 mm = 22 + pN2 + PO2.
PN2 + PO2 = 728 mm
Then you have 1/3 of 728 for N2 and 2/3 of 728 for O2.
A mixture of 0.100 mol of N2 and 0.200 mol of O2 is collected over H2O at an atmospheric pressure of 750. mm Hg and a temperature of 22 ºC. What is the partial pressure (in mmHg) of O2 in this mixture? (Vapor pressure of water @ 22 ºC is 22 mm Hg)
2 answers
485