a missile is launched an angle of 26.5 with respect to the horizontal. if it travels in the straight line over the level Terran for 2 minute and its average speed is 6000 mile per hour. what is its altitude?

Answer 1

Assume:
1. no air resistance
2. initial speed (Vi) = "average speed" = 6000 mph

Change in vertical altitude after time t
=Vi*sin(θ)t - (1/2)gt²

Vi = initial velocity = 6000 mph = 8800 ft/s
t=time since launch = 120 s.
θ=launch angle above horizontal = 26.5°
g=acceleration due to gravity = 32.2 ft/s²

Work with feet and seconds.