we know that the path follows
x(t) = v cosθ t
y(t) = 160 + v sinθ t - 4.9t^2
I will assume that the cliff and the tower are the same, otherwise I'm confused.
x(20) = 1800
y(20) = 0
So,
20v cosθ = 1800
20v sinθ = 1800
Clearly θ = π/4 and v = 127.28 m/s
y = 160 + 90t - 4.9t^2
so at t=9.18 the max height of 573.27m is attained.
A missile is fired upwards from the top of a cliff in a direction making an angle (not known ) with the horizontal. After 20seconds the projectile hits the ground at a point which is 1800metre from the foot of the tower of height 160metres. Find the angle of projection and the initial velocity of the projection and the maximum height?
1 answer
1 answer