A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles: (5 points)

An oval is formed by a rectangle with semicircles at each end. The length of the rectangle is 54 inches. The width of the rectangle is 27 inches.
Which of the following is the perimeter of the inner edge of the frame?

(π = 3.14)

192.78 inches

246.78 inches

277.56 inches

331.56 inches

1 answer

To find the perimeter of the inner edge of the frame, we need to calculate the circumference of the two semicircles at each end of the rectangle, and then add it to the combined length of the four sides of the rectangle.

The circumference of a circle is given by the formula C = πd, where d is the diameter of the circle.

The diameter of each semicircle is equal to the width of the rectangle, which is 27 inches.

So, the circumference of each semicircle is C = π(27) = 84.78 inches.

Since there are two semicircles, the total circumference contributed by the semicircles is 2 * 84.78 = 169.56 inches.

The length of the rectangle is 54 inches and the width is 27 inches, so the combined length of the four sides of the rectangle is 2(54) + 2(27) = 162 inches.

Therefore, the perimeter of the inner edge of the frame is 169.56 inches + 162 inches = 331.56 inches.

Therefore, the correct answer is 331.56 inches.