A mineral deposit along a strip of length 8 cm has density s(x)=0.07x(8−x) g/cm for 0≤x≤8. Calculate the total mass of the deposit. Your answer must include units.

Answer 1

.07 [ 8 x dx - x^2 dx ] at 8 - at 0

.07 [ 8 x^2/2 - x^3/3 ]

.07 [ 4*64 - 512/3 ]

(.07/3) [12*64 -512] = (.07/3)[256] grams