Solve this equation for time, t:
t = sound travel time + rock's time to fall
= H/345 + (2H/g)^1/2
Plug in H = 57.8 and the value of g (which you surely know) and crank away.
A mine shaft is known to be 57.8 m deep. If you would drop a rock down the shaft, how long would it take for you to hear the sound of the rock hitting the bottom of the shaft knowing that sound travels at a constant velocity of 345 m/s?
The answer is 3.60s, but I need the work. Please help!
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