To determine the number of sides of the two-dimensional vertical cross-section of a metronome shaped like a pyramid, we need to consider the structure of a pyramid. A pyramid typically has a polygonal base and triangular faces that meet at a point (the apex).
For a vertical cross-section through the center of a pyramid (assuming the base is a polygon), the cross-section will look like a triangle if sliced vertically along the apex and through the midline of the base.
Thus, if the metronome resembles a pyramid with a triangular base (which is common in many metronomes), the vertical cross-section would indeed have:
- The triangular base (which has 3 sides).
- The two sloping edges from the apex down to each vertex of the base.
Therefore, if we consider the vertices that make up the cross-section and simply the outline, the common cross-section will result in a triangle with three edges.
Thus, the number of sides in the two-dimensional vertical cross-section of a metronome, shaped like a pyramid, is 3.
The correct response is: 3.
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