A metre rule is balanced by masses of 24g and 16g suspended from its ends.Find the position of the pivot.
3 answers
24 x = 16 (100-x)
the pivot is x cm from the 24g weight, where
24x = 16(100-x)
24x = 16(100-x)
3 x= 200 - 2x
5 x = 200
x = 40
assuming that we can ignore the mass of the rule itself.
5 x = 200
x = 40
assuming that we can ignore the mass of the rule itself.