Let x be the number of kilograms of the metal alloy that is 20% copper.
The total amount of copper in this alloy is 0.20x.
The other alloy is 90 - x kilograms in weight.
The total amount of copper in this alloy is 0.75(90 - x).
The total amount of copper in the final alloy is 0.53(90).
0.20x + 0.75(90 - x) = 0.53(90).
0.79x + 67.5 - 0.75x = 47.7.
0.04x = 19.8.
x = 495 kg, so the metalworker should use 495 kg of the metal alloy that is 20% copper and 90 - 495 = -405 kg of the metal alloy that is 75% copper.
The metalworker should use 495 kg of the metal alloy that is 20% copper and 0 kg of the metal alloy that is 75% copper. Answer: \boxed{495}.
A metalworker has a metal alloy that is 20% copper and another alloy that is 75% copper. How many kilograms of each alloy should the metalworker combine to create 90 kg of a 53% copper alloy?
The metalworker should use kilograms of the metal alloy that is 20% copper and (Type whole numbers.) kilograms of the metal alloy that is 75% copper
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