Let x be the number of kilograms of the metal alloy that is 15% copper and y be the number of kilograms of the metal alloy that is 60% copper.
We know that x + y = 120 (equation 1) because the total combined weight of the two alloys is 120 kg.
We also know that 0.15x + 0.6y = 0.51 * 120 (equation 2) because the copper content in the final alloy is 51% and it is 120 kg in weight.
Simplifying equation 2, we get:
0.15x + 0.6y = 61.2
Multiply equation 1 by 0.15 and subtract it from equation 2 to eliminate x:
0.15x + 0.6y - 0.15x - 0.15y = 61.2 - 0.15 * 120
0.45y = 43.2
Dividing both sides by 0.45, we get:
y = 96
Substituting the value of y into equation 1, we get:
x + 96 = 120
x = 24
So, the metalworker should use 24 kilograms of the metal alloy that is 15% copper and 96 kilograms of the metal alloy that is 60% copper.
A metalworker has a metal alloy that is 15% copper and another alloy that is 60% copper. How many kilograms of each alloy should the metalworker combine to create 120 kg of a 51% copper alloy?
The metalworker should use __ kilograms of the metal alloy that is 15% copper and __ kilograms of the metal alloy that is 60% copper
1 answer