a metal x with relative atomic mass 56 forms an oxide with formula X2O3. how many grams of the metal will combine 10g of oxygen (o=16)
3 answers
8:48 = 5/3 : 10
4X + 3O2 ==> 2X2O3
mols O2 = 10/32 = 0.31
mols X = 0.31 x (4 mols X/3 mols O2) = about 0.42
g X = mols X*56 = ?
mols O2 = 10/32 = 0.31
mols X = 0.31 x (4 mols X/3 mols O2) = about 0.42
g X = mols X*56 = ?
23.3
0 answers