A metal X forms two different chlorides. If 12.7g of chloride A and 16.3g of chloride B contain 7.1g and 10.7g of chlorine respectively, show that the figures agrees with the law of multiple proportions. Write their formulae

Answer 1

From Google:
Law of Multiple Proportions. John Dalton (1803) stated, "'When two elements combine with each other to form two or more compounds, the ratios of the masses of one element that combines with the fixed mass of the other are simple whole numbers'.Jun 5, 2019
So we have the two chlorides that are XyClw and XyClz. We need to show that the ratio w to z are small whole numbers.
Compound A = 12.7 g X and 7.1 g Cl so X must be 5.56 g
Compound B = 16.3 g X and 10.7 g Cl so X must 5.56 g.
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7.1 x (12.7/16.3) = 5.53 g Cl for each g X
10.7 x (12/7/16.3) = 8.34 g Cl for each g X so what is the ratio of the two Cl numbers: The easy way to do this is to divide both numbers by the smaller one. That is
5.53/5.53 = 1.00
8.34/5.53 = 1.508. If we round that 1.508 to 1.50 you can see that 1.0 to 1.5 is actually 2 to 3 and those are small whole numbers. Within experimental error the law of multiple proportions is proved.
The compounds must be XCl2 and XCl3. The problem doesn't ask but I worked out the formula and X is Fe so FeCl2 and FeCl3. are the compounds.

Answer 2

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Answer 3

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Answer 4

What's the chemical formula

Answer 5

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