A metal shpere with ane excess of 11 electrons touches an identical metal sphere with an excess of 15 electrons. After the spheres touch, the number of excess electrons on the second sphere is?

Question

A metal shpere with ane excess of 11 electrons touches an identical metal sphere with an excess of 15 electrons. After the spheres touch, the number of excess electrons on the second sphere is?
My book tells me it is 13, but I don't understand why. If someone could explain, I would appreciate it truly! Thanks!

Anonymous · Accepted Answer

(11+15)/2

bobpursley · Answer

The total excess charge is divided equally. Total charge=11+15

Anonymous · Answer

The 2 spheres must have an equal amont do to magn

Anonymous · Answer

26

SONIA · Answer

BECAUSE WHEN YOU ADD 16 AND 11 YOU GET 26 16 + 11 = 26 THEN AS THE SPEARS TOUCH THEY COME TO EQUILIBRIUM OR EQUALITY. SO 26/2 26 / 2 = 13

Bob · Answer

When these two spheres come in contact, the stronger forces of repulsion on the second sphere will move two electrons onto the first sphere. When this occurs, the electrical forces will be in balance and there will be no further net movement of electrons.

Anonymous · Answer

13

Anonymous · Answer

because when two spheres come in contact, the stronger forces of repulsion on the second sphere will move two electrons onto the first sphere. When this occurs, the electrical forces will be in balance and there will be no further net movement of electrons.