The first step is to find the volume of the cube, which is (2.00cm)3 = 8.00 cm3.
Next, we need to convert the density to the same units as the volume, so we divide 6600 kg/m3 by 1,000,000 to get 6.6 g/cm3.
We can use the formula for density to find the mass of the cube:
Density = Mass/Volume
Rearranging, we get:
Mass = Density x Volume
Mass = (6.6 g/cm3) x (8.00 cm3)
Mass = 52.8 g
So the mass of the cube is 52.8 g.
Now we need to find the apparent mass when the cube is submerged in water. The cube will displace a volume of water equal to its own volume, so the apparent mass is:
Apparent mass = Mass of cube + Mass of displaced water
The density of water is 1 g/cm3, so the mass of the displaced water is:
Mass of displaced water = Density of water x Volume of displaced water
Volume of displaced water = Volume of cube = 8.00 cm3
Mass of displaced water = (1 g/cm3) x (8.00 cm3) = 8.00 g
Apparent mass = 52.8 g + 8.00 g = 60.8 g
Therefore, the apparent mass of the cube when it is totally submerged in water is 60.8 g.
A metal cube, 2.00cm on each side, has a density of 6600 kg/m3.
Find its apparent mass when it is totally submerged in water.
1 answer
1 answer