a metal ball with a charge of 5.4x10^8 electrons is touched to another metal ball so that all the excess electrons are shared equally. What is the final cahrge on the first ball?

Answer 1

5.4•10^8/2 =2.7•10^8.
q = N•e= 2.7•10^8•1.6•10^-19 =
=4.33•10^-11 C