A merry-go-round with a a radius of R = 1.95 m and moment of inertia I = 192 kg-m2 is spinning with an initial angular speed of ω = 1.41 rad/s in the counter clockwise direection when viewed from above. A person with mass m = 63 kg and velocity v = 4.7 m/s runs on a path tangent to the merry-go-round. Once at the merry-go-round the person jumps on and holds on to the rim of the merry-go-round.
What is the angular speed of the merry-go-round after the person lets go?
I tried W=IW+MVR/MR^2+I but I don't think that's right
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