A menu in a restaurant allows you to pick some items from Column A and some from Column B. Column A has 24 items. Column B has 16 items. If you and 3 friends want to order everything from both columns, but not order any item more than once, how many items from each column would you each choose (assuming each person orders the same number of items from each column)?

Question

Select the correct answer.

Question 6 options:

6 from A, 4 from B

4 from A, 4 from B

4 from A, 6 from B

6 from A, 6 from B

Answer 1

Each person wants to order the same number of items from each column. Let's assume that each person chooses x items from Column A and x items from Column B.

Since there are 24 items in Column A and 16 items in Column B, the total number of items selected from both columns is 24x + 16x = 40x.

Since there are 4 people in total, the total number of items selected from both columns must be divisible by 4.

The only option that satisfies this condition is 4 from A, 4 from B.

Therefore, each person would choose 4 items from Column A and 4 items from Column B.

The correct answer is 4 from A, 4 from B.