A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx

Question

to try and figure out which membership would be cheaper for a year. What is the value of k
for the cheaper membership?(1 point)
Remaining Attempts : 3

Answer 1

To compare the costs of the two gym memberships over a year, we first need to express the memberships in terms of a cost per month.

Gym A:

• Cost: $50 for 5 months
• Cost per month: \( \frac{50}{5} = 10 \)
• Therefore, the equation for Gym A can be written as: \[ y = 10x \] where \( y \) is the total cost and \( x \) is the number of months.

Gym B:

• Cost: $40 for 3 months
• Cost per month: \( \frac{40}{3} \approx 13.33 \)
• Therefore, the equation for Gym B can be written as: \[ y \approx 13.33x \]

Now to find the total cost for each gym membership for 12 months:

1. For Gym A: \[ y = 10(12) = 120 \]

2. For Gym B: \[ y \approx 13.33(12) \approx 160 \]

Now we can compare the total costs for the year:

• Gym A costs $120 for a year.
• Gym B costs approximately $160 for a year.

Thus, Gym A is the cheaper membership.

The value of \( k \) for the cheaper membership (Gym A) is 10.