A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership

Answer 1

Let's assume that a year consists of 12 months.
For Gym A, the equation in the form of y=kx would be:
y = 50/5 * x
Dividing both the numerator and denominator by 5, we get:
y = 10x
So for Gym A, k = 10.

For Gym B, the equation in the form of y=kx would be:
y = 40/3 * x
Dividing both the numerator and denominator by 3, we get:
y = 13.33x (rounded to 2 decimal places)
So for Gym B, k = 13.33.

Therefore, the value of k for the cheaper membership is 10.

Answer 2

Two equations are written to express how far a car can go when driving on different roads. On Road 1, the car can go 60 miles in 2 hours. On Road 2, the car can go 90 miles in 4 hours. Write an equation where y is the distance in miles and x is the time in hours to represent the motion of the faster car

Answer 3

Let's assume that the faster car represents the car driving on Road 2.

For Road 2, the car can go 90 miles in 4 hours. We can use this information to write the equation in the form of y = kx:

y = kx

We know that on Road 2, the car can go 90 miles in 4 hours. We can substitute these values into the equation:

90 = k * 4

Now, we can solve for k:

k = 90 / 4

k = 22.5

Therefore, the equation representing the motion of the faster car on Road 2 is:

y = 22.5x