The question does not make sense.
a t / t ^ 2 =
3 t / t ^ 2 =
3 t / ( t * t ) =
3 / t
a t / t ^ 2 + b =
3 t / t ^ 2 + 1 =
3 / t + 1
Tends to infinity as x tends towards 0.
A medicine in the bloodstream has a concentration of c(t) =at/t^2 + b where a=3 and b=1
Approximate the highest concentration of the medicine reached in the bloodstream
Find algebraically when c(t) less then Sign 0.5
5 answers
How would i approximate the highest concentration reached in the bloodstream
Not at all.
highest concentration = infinity as x tends towards 0.
highest concentration = infinity as x tends towards 0.
The question also states to determine how long it takes for the medicine to drop below 0.2 how could i do this
Rose, it was pointed out to you by Bosnian that your question makes no sense, yet you keep asking questions pertaining to it.
your equation is
c(t) = 3t/t^2 + 1
which reduces to
c(t) = 3/t + 1
Even at the beginning, when t=0, this would be undefined.
That is, the concentration would be infinitely huge, rather silly, don't you think?
the graph looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+3%2Fx+%2B+1
As t gets larger, c(t) will approach 1
for c(t) < .5
3/t < .5
3 < .5t
t > 6
the graph confirms this
your equation is
c(t) = 3t/t^2 + 1
which reduces to
c(t) = 3/t + 1
Even at the beginning, when t=0, this would be undefined.
That is, the concentration would be infinitely huge, rather silly, don't you think?
the graph looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+3%2Fx+%2B+1
As t gets larger, c(t) will approach 1
for c(t) < .5
3/t < .5
3 < .5t
t > 6
the graph confirms this