work = force * distance
f = 5497 / 22.1
a = f / m = 5497 / (22.1 * 3090)
d = 1/2 a t^2
... t = √(2d / a)
v = a t
A mechanic pushes a 3090 kg car from rest
to a speed of v, doing 5497 J of work in the
process. During this time, the car moves
22.1 m.
Find the speed v. Neglect friction between
car and road.
Answer in units of m/s.
1/2mv^2 doesnt work
1 answer