A Maths Applied student holidaying in Sydney notices that the Centrepoint tower has an angle of elevation of 15deg20'. After walking 400m directly towards the tower she now observes the elevation to be 24deg33'

Answer 1

I assume you are talking about angles of elevation, and want to find the height of the tower.

If she ends up x meters from the tower, then

h/x = sin 24°33'
h/(x+400) = sin 15°20'

equating the values for x,

h/sin 24°33' = h/sin 15°20' - 400
h/.415 = h/.264 - 400
h = 290.23

Answer 2

I assume you are talking about angles of elevation, and want to find the height of the tower.

If she ends up x meters from the tower, then

h/x = tan 24°33'
h/(x+400) = tan 15°20'

equating the values for x,

h/tan 24°33' = h/tan 15°20' - 400
h/.45678 = h/.27419 - 400
h = 274.37

Answer 3

How would I find out how far away from the base of the tower she was when she made her first measurement of 15deg20'