A mathematics teacher wanted to see the correlation between test scores and homework. The homework grade (x) and test grade (y) are given in the accompanying table. Write the linear regression equation that represents this set of data, rounding all coefficients to the nearest tenth. Using this equation, find the projected test grade, to the nearest integer, for a student with a homework grade of 37.

Homework Grade (x) Test Grade (y)
7171 6565
8787 8686
8585 8080
7373 7878
7373 6868
9090 7777
8686 9090
Answer
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Regression Equation:

Final Answer:
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To determine the linear regression equation for the given dataset, we'll first need to summarize the data:

| Homework Grade (x) | Test Grade (y) | |---------------------|-----------------| | 71 | 65 | | 87 | 86 | | 85 | 80 | | 73 | 78 | | 73 | 68 | | 90 | 77 | | 86 | 90 |

Next, we can calculate the necessary statistics to find the linear regression coefficients \( b_0 \) (intercept) and \( b_1 \) (slope).

  1. Calculate the means of x and y:

\[ \bar{x} = \frac{71 + 87 + 85 + 73 + 73 + 90 + 86}{7} = \frac{ 525}{7} = 75 \] \[ \bar{y} = \frac{65 + 86 + 80 + 78 + 68 + 77 + 90}{7} = \frac{ 534}{7} = 76.3 \]

  1. Calculate b1 (slope):

\[ b_1 = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2} \]

Calculating these values step by step:

  • Compute \(x_i - \bar{x}\) and \(y_i - \bar{y}\):

| \(x_i\) | \(y_i\) | \(x_i - \bar{x}\) | \(y_i - \bar{y}\) | \((x_i - \bar{x})(y_i - \bar{y})\) | \((x_i - \bar{x})^2\) | |---------|---------|---------------------|---------------------|-------------------------------------|-----------------------| | 71 | 65 | -4 | -11.3 | 45.2 | 16 | | 87 | 86 | 12 | 9.7 | 116.4 | 144 | | 85 | 80 | 10 | 3.7 | 37 | 100 | | 73 | 78 | -2 | 1.7 | -3.4 | 4 | | 73 | 68 | -2 | -8.3 | 16.6 | 4 | | 90 | 77 | 15 | 0.7 | 10.5 | 225 | | 86 | 90 | 11 | 13.7 | 150.7 | 121 |

Next, we sum the necessary components: \[ \sum (x_i - \bar{x})(y_i - \bar{y}) = 45.2 + 116.4 + 37 - 3.4 + 16.6 + 10.5 + 150.7 = 372 \] \[ \sum (x_i - \bar{x})^2 = 16 + 144 + 100 + 4 + 4 + 225 + 121 = 614 \]

Now we can calculate \(b_1\): \[ b_1 = \frac{372}{614} \approx 0.606 (rounded\ to\ nearest\ tenth,\ 0.6) \]

  1. Calculate b0 (intercept): \[ b_0 = \bar{y} - b_1\bar{x} = 76.3 - 0.606(75) \approx 76.3 - 45.45 = 30.85 \approx 30.9 \]

Thus, the linear regression equation is: \[ y = 30.9 + 0.6x \]

Now use this regression equation to find the projected test grade for a homework grade of 37: \[ y = 30.9 + 0.6(37) = 30.9 + 22.2 = 53.1 \approx 53 \text{ (to the nearest integer)} \]

Final Answer:

  • Regression Equation: \(y = 30.9 + 0.6x\)
  • Projected Test Grade for Homework Grade 37: 53