A mass of air at 20c has relative humidity 36% if the air is cooled at 16c ,what will its relative humidity be? Saturation vapour pressure at 20c and 16c are 17.5mmhg and 13.6mmhg respectively

1 answer

To find the relative humidity (RH) at the new temperature (16°C), we can follow these steps:

  1. Find the actual vapor pressure (VP) at 20°C: The relative humidity is given by the formula:

    \[ \text{RH} = \frac{\text{VP}}{\text{SVP}} \times 100 \]

    Where:

    • RH = relative humidity (%)
    • VP = actual vapor pressure
    • SVP = saturation vapor pressure

    Rearranging the formula to find the VP:

    \[ \text{VP} = \frac{\text{RH}}{100} \times \text{SVP} \]

    Substituting the values for 20°C:

    \[ \text{VP} = \frac{36}{100} \times 17.5, \text{mmHg} \]

    \[ \text{VP} = 0.36 \times 17.5, \text{mmHg} = 6.3, \text{mmHg} \]

  2. Find the new relative humidity at 16°C: Now, we know the actual vapor pressure (VP) remains the same when the air is cooled. We need to find the new relative humidity at 16°C using the saturation vapor pressure at that temperature (13.6 mmHg):

    Using the RH formula again:

    \[ \text{RH}{16} = \frac{\text{VP}}{\text{SVP}{16}} \times 100 \]

    Substituting the values:

    \[ \text{RH}_{16} = \frac{6.3, \text{mmHg}}{13.6, \text{mmHg}} \times 100 \]

    \[ \text{RH}_{16} = \frac{6.3}{13.6} \times 100 \approx 46.32% \]

Therefore, the relative humidity when the air is cooled to 16°C will be approximately 46.32%.