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A mass of 2kg is dropped from a height of 3m.Neglecting air resistance,KE of the stone just b4 it hits the ground is ?

3 answers

KE = 0.5M*V^2.

V^2 = Vo^2 + 2g*h = 0 + 19.6*3 = 58.8.

and of course, the final KE is equal to the initial PE...
initial PE=mgh=2*9.8*3=58.8Joules

Yes, I agree.

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