A mass m1 = 18.7 kg on a frictionless ramp is attached to a light string. The string passes over a frictionless pulley and is attached to a hanging mass m2. The ramp is at an angle of θ = 23.7° above the horizontal. m1 moves up the ramp uniformly (at constant speed). Find the value of m2.

Answer 1

Let tension in string = T

m2 g = T since there is no acceleration

now draw forces on m1 up and down ramp

T = up ramp force
m1 g sin 23.7 = force down ramp

net force up ramp = m1 a = 0
so
T = m1 g sin 23.7

so
m2 g = m1 g sin 23.7
m2 = m1 sin 23.7

Answer 2

unit of measurement required??? waht is answer exactly of m2??

Answer 3

mass of m1 is given in kg
so m2 is in kg
now I am sure you can do 18.7 * sin 23.7

Answer 4

thanks a lotttttttt