You want to find where
30t - 4.9t^2 = 60 - 4.9(t-.5)^2
t = 2.34
now plug that in to find either height.
Assuming you meant 60m above where the first mass started. Things are different if the second mass is dropped when the first mass is 60m below it. But I'm sure you can make the adjustments needed. If not, c'mon back and show whatcha got.
a mass is thrown vertically upwards with
an initial velocity of 30m/s. a second mass is
dropped 0.5s later from directly above a height of
60m from the first mass. when do they meet and
at what height?
1 answer
1 answer