wouldn't that depend on the spring?
2PI/period=sqrt(k/m)
k/m= (2PI/5)^2
force=kx
x=force/k= mg/k= 9.8*(5/2PI)^2
check that.
a mass is suspended on a vertical spring oscillates with a period of 0.5 sec .When the mass is attached to the spring and allowed to hang at rest .By how much is the spring stretched?
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