a mass is suspended on a vertical spring oscillates with a period of 0.5 sec .When the mass is attached to the spring and allowed to hang at rest .By how much is the spring stretched?

1 answer

wouldn't that depend on the spring?

2PI/period=sqrt(k/m)

k/m= (2PI/5)^2

force=kx
x=force/k= mg/k= 9.8*(5/2PI)^2
check that.