Two things you should be aware of. First, it is 2.5 LITERS (not litter).
Second, the density of water is 1000 kg/m3.
First, how much heat do we get from burning 20.0 g petrol. That is
43,640 kJ x (20.0 g/1000 g) = 872.8 kJ. How will the temperature of the water change. That is q = mass H2O x specific heat H2O x delta T
872.8 kJ = 2.5 kg x 4.18 kJ/kg*C x delta T.
Solve for delta T.
Post your work if you get stuck.
A mass has 20.0g of petrol was burnt in air the heat produce wlalsl usedto heat 2.5litter of water given that
the heat value of petrol is 43640kjkg what was the temperature change in water?specific heat capàcity of waters.4.18kjkg-1k-1density of water 1000kg3
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