1/2 g t^2 = .75 m ... t^2 = 1.5 m / g
... solve for t
horizontal distance = .14 m/s * t
A marble with speed 14 cm/s rolls off the edge of a table 75 cm high. How long does it take to drop to the floor? How far, horizontally, from the table edge does the marble strike the floor?
2 answers
hf=hi+vi*t+1/2 h t^2 with hf=0, hi=.75, g=9.8m/s^2 then
0=.75 -1/2 g t^2
thus 1/2 g t^2=.75
horizontal distance= horizontal velocity*time
=.14m/s * time
0=.75 -1/2 g t^2
thus 1/2 g t^2=.75
horizontal distance= horizontal velocity*time
=.14m/s * time
2 answers