A manufacturer wants to produce a 4"× 2"× 5"

Question

rectangular box to hold teabags using the net shown.
Study the box and the net.
Then complete the statements below to find the surface area of the box.

Answer 1

To find the surface area of the box, we need to calculate the area of each face of the box using the given dimensions.

The dimensions of the box are:
- Length: 4 inches
- Width: 2 inches
- Height: 5 inches

1. There are two rectangles that make up the top and bottom faces of the box. The dimensions of each rectangle are 4 inches by 2 inches. Therefore, the area of each rectangle is (4 inches) * (2 inches) = 8 square inches. Since there are two of these rectangles, their total area is 8 square inches * 2 rectangles = 16 square inches.

2. There are two rectangles that make up the front and back faces of the box. The dimensions of each rectangle are 4 inches by 5 inches. Therefore, the area of each rectangle is (4 inches) * (5 inches) = 20 square inches. Since there are two of these rectangles, their total area is 20 square inches * 2 rectangles = 40 square inches.

3. There are two rectangles that make up the left and right faces of the box. The dimensions of each rectangle are 2 inches by 5 inches. Therefore, the area of each rectangle is (2 inches) * (5 inches) = 10 square inches. Since there are two of these rectangles, their total area is 10 square inches * 2 rectangles = 20 square inches.

Finally, to find the total surface area of the box, we sum up the areas of all the faces:
16 square inches + 40 square inches + 20 square inches = 76 square inches.

Therefore, the surface area of the box is 76 square inches.